banshuai
路人甲
路人甲
  • 注册日期2011-12-17
  • 发帖数2
  • QQ
  • 铜币111枚
  • 威望0点
  • 贡献值0点
  • 银元0个
阅读:2436回复:1

GIS问题求解

楼主#
更多 发布于:2011-12-17 20:30
请问图幅的接边处理原则都有哪些?? 有知道的的吗 求知道啊 谢谢了!!!
喜欢0 评分0
fxkulou
路人甲
路人甲
  • 注册日期2012-02-12
  • 发帖数10
  • QQ464851637
  • 铜币120枚
  • 威望0点
  • 贡献值0点
  • 银元0个
1楼#
发布于:2012-03-20 00:49
<p:colorscheme colors="#ffffff,#000000,#808080,#000000,#bbe0e3,#333399,#009999,#99cc00">

<div v:shape="_x0000_s1026" class="O">

<div style="text-align:justify;mso-line-spacing:"90 20="20"  0";mso-margin-left-alt:
216;mso-char-wrap:1;mso-kinsoku-overflow:1"><nobr><span style="font-size:178%"><span style="mso-special-format:bullet;position:absolute;left:-8.13%;text-align:left">?</span></span><font class="Apple-style-span" size="2"><span lang="EN-US"><b>1</b></span><span style="font-family: 宋体; "><b>.</b></span><span lang="EN-US"><b>4</b></span><span style="font-family: 宋体; "><b>.</b></span><span lang="EN-US"><b>2</b></span><span style="font-family: 宋体; "><b>图像拼接</b></span><span lang="EN-US"><b>/</b></span><span style="font-family: 宋体; "><b>裁剪
</b></span></font></nobr></div>

<div><font class="Apple-style-span" size="1"><span lang="EN-US"><b>1</b></span><span style="font-family: 宋体; "><b>)图像拼接
</b></span></font></div>

<div><font class="Apple-style-span" size="1"><b>     </b><span style="font-family: 宋体; "><b>以两相邻地图图像的部分重叠区为基础,把它</b></span><span style="font-family: 宋体; "><b>们合成为一幅整图的过程叫做图像拼接,分上</b></span><span style="font-family: 宋体; "><b>下拼接和左右拼接。以左右拼接为例,取左图</b></span><span style="font-family: 宋体; "><b>右边缘一个矩形区域</b></span><span lang="EN-US"><b>A</b></span><span style="font-family: 宋体; "><b>,取右图左边缘一个矩</b></span><span style="font-family: 宋体; "><b>形区域</b></span><span lang="EN-US"><b>B</b></span><span style="font-family: 宋体; "><b>,如果</b></span><span lang="EN-US"><b>A</b></span><span style="font-family: 宋体; "><b>和</b></span><span lang="EN-US"><b>B</b></span><span style="font-family: 宋体; "><b>有一定的重叠区,可以利</b></span><span style="font-family: 宋体; "><b>用计算机实现自动的匹配,其拼接算法如下:
</b></span></font></div>

<div><span style="mso-special-format:
bullet;position:absolute;left:-3.56%"><font class="Apple-style-span" size="1">?</font></span><font class="Apple-style-span" size="1"><span style="font-family: 宋体; "><b>由</b></span><span lang="EN-US"><b>A</b></span><span style="font-family: 宋体; "><b>中右侧边缘从右至左依次取若干个列</b></span><span lang="EN-US"><b>L1</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>O</b></span><span style="font-family: 宋体; "><b>),</b></span><span lang="EN-US"><b>L1</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>1</b></span><span style="font-family: 宋体; "><b>),</b></span><span lang="EN-US" style="font-family: Arial; "><b>…</b></span><span style="font-family: 宋体; "><b>,</b></span><span lang="EN-US"><b>L1</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>n</b></span><span style="font-family: 宋体; "><b>),以各列内像</b></span><span style="font-family: 宋体; "><b>素灰度的长度序列为特征向量,分别求出以上</b></span><span style="font-family: 宋体; "><b>各列的特征向量</b></span><span lang="EN-US"><b><i>V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>O</i></b></span><span style="font-family: 宋体; "><b><i>),</i></b></span><span lang="EN-US"><b><i>V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>1</i></b></span><span style="font-family: 宋体; "><b><i>),</i></b></span><span lang="EN-US" style="font-family: Arial; "><b><i>…</i></b></span><span style="font-family: 宋体; "><b><i>,</i></b></span><span lang="EN-US"><b><i>V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>n</i></b></span><span style="font-family: 宋体; "><b><i>)</i></b></span><span style="font-family: 宋体; "><b>。</b></span>?</font></div><p:colorscheme colors="#ffffff,#000000,#808080,#000000,#bbe0e3,#333399,#009999,#99cc00"><font class="Apple-style-span" size="1">

<div v:shape="_x0000_s1026" class="O">

<div><span style="font-family: 宋体; "><b>自动拼接</b></span><b> </b><span style="font-family: 宋体; "><b>即由</b></span><span lang="EN-US"><b>B</b></span><span style="font-family: 宋体; "><b>中左侧从左至右依次取若干列</b></span><span lang="EN-US"><b>L2</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>n</b></span><span style="font-family: 宋体; "><b>),</b></span><span lang="EN-US"><b>L2</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>n-1</b></span><span style="font-family: 宋体; "><b>),</b></span><span lang="EN-US" style="font-family: Arial; "><b>…</b></span><span style="font-family: 宋体; "><b>,</b></span><span lang="EN-US"><b>L2</b></span><span style="font-family: 宋体; "><b>(</b></span><span lang="EN-US"><b>O</b></span><span style="font-family: 宋体; "><b>),以各列内像素灰</b></span><span style="font-family: 宋体; "><b>度的长度序列为特征向量,分别求出以上各列的特征</b></span><span style="font-family: 宋体; "><b>向量</b></span><span lang="EN-US"><b><i>V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>n</i></b></span><span style="font-family: 宋体; "><b><i>):</i></b></span><span lang="EN-US"><b><i>V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>n-1</i></b></span><span style="font-family: 宋体; "><b><i>),</i></b></span><span lang="EN-US" style="font-family: Arial; "><b><i>…</i></b></span><span style="font-family: 宋体; "><b><i>,</i></b></span><span lang="EN-US"><b><i>V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>O</i></b></span><span style="font-family: 宋体; "><b><i>)</i></b></span><span style="font-family: 宋体; "><b>。若向量序</b></span><span style="font-family: 宋体; "><b>列</b></span><span lang="EN-US"><b><i>[V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>O</i></b></span><span style="font-family: 宋体; "><b><i>);</i></b></span><span lang="EN-US"><b><i>V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>1</i></b></span><span style="font-family: 宋体; "><b><i>)</i></b></span><span lang="EN-US"><b><i>,</i></b></span><span lang="EN-US" style="font-family: Arial; "><b><i>…</i></b></span><span style="font-family: 宋体; "><b><i>,</i></b></span><span lang="EN-US"><b><i>V1</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>n</i></b></span><span style="font-family: 宋体; "><b><i>)]</i></b></span><span style="font-family: 宋体; "><b>和</b></span><span lang="EN-US"><b><i>[V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>O</i></b></span><span style="font-family: 宋体; "><b><i>),</i></b></span><span lang="EN-US"><b><i>V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>1</i></b></span><span style="font-family: 宋体; "><b><i>),</i></b></span><span lang="EN-US" style="font-family: Arial; "><b><i>…</i></b></span><span style="font-family: 宋体; "><b><i>,</i></b></span><span lang="EN-US"><b><i>V2</i></b></span><span style="font-family: 宋体; "><b><i>(</i></b></span><span lang="EN-US"><b><i>n</i></b></span><span style="font-family: 宋体; "><b><i>)]</i></b></span><span style="font-family: 宋体; "><b>匹配,则转向步骤</b></span><span lang="EN-US"><b>4</b></span><span style="font-family: 宋体; "><b>。
</b></span></div>

<div><span style="mso-special-format:
bullet;position:absolute;left:-3.55%">?</span><span style="font-family: 宋体; "><b>人工拼接</b></span><b> </b><span style="font-family: 宋体; "><b>即固定</b></span><span lang="EN-US"><b>A</b></span><span style="font-family: 宋体; "><b>,通过人机交互控制</b></span><span lang="EN-US"><b>B</b></span><span style="font-family: 宋体; "><b>以一定步长</b></span><span style="font-family: 宋体; "><b>上下左右移动,直到</b></span><span lang="EN-US"><b>A</b></span><span style="font-family: 宋体; "><b>和</b></span><span lang="EN-US"><b>B</b></span><span style="font-family: 宋体; "><b>重叠区对齐为止。
</b></span></div>

<div><span style="mso-special-format:
bullet;position:absolute;left:-3.49%">?</span><span style="font-family: 宋体; "><b>根据步骤</b></span><span lang="EN-US"><b>2</b></span><span style="font-family: 宋体; "><b>匹配情况或步骤</b></span><span lang="EN-US"><b>3</b></span><span style="font-family: 宋体; "><b>的偏移情况对两相邻地图</b></span><span style="font-family: 宋体; "><b>图像进行修正和合成。</b></span>?</div><p:colorscheme colors="#ffffff,#000000,#808080,#000000,#bbe0e3,#333399,#009999,#99cc00">

<div v:shape="_x0000_s1026" class="O">

<div><span style="font-family: 宋体; ">在对底图进行数字化以后,由于图幅比较大或者使用小型数字</span><span style="font-family: 宋体; ">化仪时,难以将研究区域的底图以整幅的形式来完成,这是需</span><span style="font-family: 宋体; ">要将整个图幅划分成几部分分别输入。在所有部分都输入完毕</span><span style="font-family: 宋体; ">并进行拼接时,常常会有边界不一致的情况,需要进行边缘匹</span><span style="font-family: 宋体; ">配处理(图</span><span lang="EN-US">2-5</span><span style="font-family: 宋体; ">)。边缘匹配处理,类似于下面提及的悬挂节点</span><span style="font-family: 宋体; ">处理,可以由计算机自动完成,或者辅助以手工半自动完成。
</span></div>

<div><span style="mso-special-format:
bullet;position:absolute;left:-3.54%">?</span><span style="font-family: 宋体; ">除了图幅尺寸的原因,在</span><span lang="EN-US">GIS</span><span style="font-family: 宋体; ">实际应用中,由于经常要输入标</span><span style="font-family: 宋体; ">准分幅的地形图,也需要在输入后进行拼接处理,这时,</span><span style="font-family: 宋体; color: rgb(255, 51, 0); ">一般</span><span style="font-family: 宋体; color: rgb(255, 51, 0); ">需要先进行投影变换,通常的做法是从地形图使用的高斯</span><span lang="EN-US" style="font-family: Arial; color: rgb(255, 51, 0); ">——</span><span style="font-family: 宋体; color: rgb(255, 51, 0); ">克吕格投影转换到经纬度坐标系中,然后再进行拼接</span><span style="font-family: 宋体; ">。</span></div><div><span style="font-family: 宋体; "><br/></span></div><div><font class="Apple-style-span" face="宋体">老师的课件,貌似原则还是要自己归纳也。。。</font></div></div></p:colorscheme></div></font></p:colorscheme></div></p:colorscheme>
举报 回复(0) 喜欢(0)     评分
游客

返回顶部